Question

Using suitable chemicals from the box, write balanced chemical equations for the preparation of the following salts: Lead (II) carbonate, Copper (II) chloride, Iron (II) chloride.

Hint:

To prepare an insoluble salt like Lead Carbonate, you must always start with two soluble reactants!

Answer 1

The box of chemicals is not visible in the question you sent, so I am using the most common suitable chemicals generally used for preparing these salts.

1. Preparation of Lead (II) carbonate
Lead (II) carbonate is an insoluble salt, so it is prepared by precipitation using a soluble lead salt and a soluble carbonate.

Balanced equation:
Pb(NO₃)₂ + Na₂CO₃ → PbCO₃↓ + 2NaNO₃

Here, lead(II) nitrate reacts with sodium carbonate to give a white precipitate of lead(II) carbonate.

2. Preparation of Copper (II) chloride
Copper (II) chloride can be prepared by reacting copper(II) oxide with hydrochloric acid.

Balanced equation:
CuO + 2HCl → CuCl₂ + H₂O

In this reaction, the base copper(II) oxide reacts with hydrochloric acid to form copper(II) chloride and water.

3. Preparation of Iron (II) chloride
Iron (II) chloride is prepared by reacting iron with dilute hydrochloric acid.

Balanced equation:
Fe + 2HCl → FeCl₂ + H₂↑

Here, iron displaces hydrogen from hydrochloric acid and forms iron(II) chloride.

Final Answers:
Pb(NO₃)₂ + Na₂CO₃ → PbCO₃↓ + 2NaNO₃
CuO + 2HCl → CuCl₂ + H₂O
Fe + 2HCl → FeCl₂ + H₂↑

Note:
If you send the box of chemicals, I will rewrite the answer using only those exact chemicals.