Using Einstein's photoelectric equation, the graphical representation between the kinetic energy (E) of emitted Photoelectrons and the frequency of incident radiation (\(ν\)) is show correctly in figure
Show Hint
No electrons are emitted below the threshold frequency; above it, E rises linearly.
Step 1: Intercepts:
Put $E_k = 0$: $\nu = W_0/h = \nu_0$, the intercept on the $\nu$ axis. At $\nu = 0$, $E_k = -W_0$, a negative value, which is not physical.
Step 2: Slope:
The slope is $h$, a positive constant, so the line rises.
Step 3: Pick the picture:
Only graph (C) begins on the frequency axis at $\nu_0$ and rises with slope $h$.
Final Answer:
Graph C shows the threshold and linear rise.
\[ \boxed{\text{(C) }\text{Graph (C)}} \]
