| Isotope | Isotopic molar mass | Abundance |
| 36Ar | 35.96755 g mol–1 | 0.337% |
| 38Ar | 37.96272 g mol–1 | 0.063% |
| 40Ar | 39.9624 g mol–1 | 99.600% |
Given:
Naturally occurring isotopes of argon and their data:
| Isotope | Isotopic molar mass (g mol−1) | Abundance (%) |
|---|---|---|
| 36Ar | 35.96755 | 0.337 |
| 38Ar | 37.96272 | 0.063 |
| 40Ar | 39.9624 | 99.600 |
Step 1: Convert percentage abundance into fractional abundance
36Ar = 0.337 / 100 = 0.00337
38Ar = 0.063 / 100 = 0.00063
40Ar = 99.600 / 100 = 0.99600
Step 2: Calculate average molar mass of argon
Average molar mass = Σ (Isotopic mass × Fractional abundance)
= (35.96755 × 0.00337) + (37.96272 × 0.00063) + (39.9624 × 0.99600)
= 0.1212 + 0.0239 + 39.8026
= 39.95 g mol−1
Final Answer:
The molar mass of naturally occurring argon is:
39.95 g mol−1
Calculate the number of moles present in 9.10 × 1016 kg of water.