Two springs with spring constants \(K_1 = 1500 \, \text{N/m}\) and \(K_2 = 3000 \, \text{N/m}\) are stretched by the same force. The ratio of potential energy stored in spring will be
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The potential energy stored in a spring is inversely proportional to its spring constant when the same force is applied.
The formula for potential energy in a spring is:
\[
E = \frac{1}{2} k x^2
\]
Because the springs experience the same force, their stretch \(x\) is tied inversely to the spring constant \(k\). Therefore, the potential energy ratio is \(4 : 1\).