Question:medium

Two soap bubbles each with radius \(r_1\) and \(r_2\) coalesce in vacuum under isothermal conditions to form a bigger bubble of radius \(R\). Then \(R\) is equal to

Show Hint

In a vacuum under isothermal conditions, simply remember that the square of the final radius is the sum of the squares of the individual radii: \(R^2 = \sum r_i^2\).
Updated On: May 6, 2026
  • \(\sqrt{r_1^2 + r_2^2}\)
  • \(\sqrt{r_1^2 - r_2^2}\)
  • \(r_1 + r_2\)
  • \(\frac{\sqrt{r_1^2 + r_2^2}}{2}\)
  • \(2\sqrt{r_1^2 + r_2^2}\)
Show Solution

The Correct Option is A

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