Question:medium

Two-point charges, $q_1 = 36\ \mu\text{C}$ and $q_2 = -9\ \mu\text{C}$ are placed at a distance of $30\text{ cm}$. What distance from $q_1$, where the net electric field is zero, will be:

Show Hint

For two point charges $q_1$ and $q_2$ separated by $r$, the distance of the neutral point from the smaller charge $q_2$ is $x = \frac{r}{\sqrt{q_1/q_2} \pm 1}$. Use $+$ if charges are opposite, $-$ if they are same.
Updated On: May 13, 2026
  • $10\text{ cm}$
  • $20\text{ cm}$
  • $60\text{ cm}$
  • $30\text{ cm}$
Show Solution

The Correct Option is C

Solution and Explanation

Was this answer helpful?
0

Top Questions on Electric field and potential due to point


Questions Asked in CUET (UG) exam