Question:medium

Two pipes A and B would fill a cistern in 30 and 40 minutes respectively. Both pipes are opened. Determine the time the first pipe can be turned off so that the cistern may be just filled in 20 minutes?

Updated On: Nov 25, 2025
  • After 10 minutes
  • After 15 minutes
  • After 20 minutes
  • After 22 minutes
  • After 25 minutes
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The Correct Option is B

Solution and Explanation

The correct answer is option (B):
After 15 minutes

Here's how to solve this problem, explaining the reasoning step-by-step:

First, understand the work rate:

* Pipe A fills the cistern in 30 minutes, so it fills 1/30 of the cistern per minute.
* Pipe B fills the cistern in 40 minutes, so it fills 1/40 of the cistern per minute.

Second, consider the combined work:

* Let's say Pipe A is turned off after 'x' minutes.
* Pipe B is open for the entire 20 minutes.

Third, set up an equation representing the filled cistern:

* Work done by A in 'x' minutes: (x/30)
* Work done by B in 20 minutes: (20/40) = 1/2
* Combined work (equal to the full cistern which is represented by the value of 1): (x/30) + (1/2) = 1

Fourth, solve for 'x':

* Subtract 1/2 from both sides: (x/30) = 1/2
* Multiply both sides by 30: x = 15

Therefore, Pipe A must be turned off after 15 minutes to allow the cistern to be filled in a total of 20 minutes.
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