Question:medium

Two particles of masses \(m_1\) and \(m_2\) having charges \(q_1\) and \(q_2\) respectively are projected with the same velocity in a region of uniform magnetic field \(\vec{B}\) pointing vertically upward. If they describe circular paths as shown in the figure, one may conclude that :

Show Hint

When tracking particles in magnetic field problems, always remember that the radius of a circular trajectory is directly proportional to the mass-to-charge ratio (\(m/q\)) when the velocity \(v\) and field \(B\) are held constant: \[ R \propto \frac{m}{q} \] A smaller radius directly implies a smaller value of \(\frac{m}{q}\). Therefore, seeing that curve 1 is tighter (\(R_1 < R_2\)), you can immediately write \(\frac{m_1}{q_1} < \frac{m_2}{q_2}\) and cross-multiply to reach the final answer in seconds.
  • \(\frac{m_1}{m_2} > \frac{q_1}{q_2}\)
  • \(\frac{m_1}{m_2} > \frac{q_2}{q_1}\)
  • \(\frac{m_1}{m_2} < \frac{q_1}{q_2}\)
  • \(\frac{m_1}{m_2} < \frac{q_2}{q_1}\)
Show Solution

The Correct Option is C

Solution and Explanation

Was this answer helpful?
0