Question

Two inductors of \(80 \text{ mH}\) each are joined in parallel. If the current is \(2.1 \text{ A}\), the energy stored in the combination is

• A. \(4.84 \times 10^{-2} \text{ J}\)
• B. \(7.26 \times 10^{-2} \text{ J}\)
• C. \(8.82 \times 10^{-2} \text{ J}\)
• D. \(10.85 \times 10^{-2} \text{ J}\)

Hint:

Inductors in parallel combine like resistors in parallel.

Answer 1

The Correct Option is C