Question:easy

Two forces P and Q acting at \(\theta\) the resultant force R is given by

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This resultant formula is a fundamental relation in vector mechanics. You can quickly verify its validity using special cases:
- For \(\theta = 0\ ^\circ\) (parallel forces): \(R = P + Q\).
- For \(\theta = 90\ ^\circ\) (perpendicular forces): \(R = \sqrt{P^2 + Q^2}\).

Updated On: Jul 23, 2026

\(R = \sqrt{P^2 + Q^2 + 2PQ\sin2\theta}\)
\(R = \sqrt{P^2 + Q^2 + 2PQ\cos\theta}\)
\(R = \sqrt{P^2 + Q^2 - 2PQ\sin2\theta}\)
\(R = \sqrt{P^2 + Q^2 + 2PQ\cos2\theta}\)

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The Correct Option is B

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Top Questions on Engineering Mathematics

The integer value printed by the ANSI-C program given below is ________.


int funcp(){
    static int x = 1;
    x++;
    return x;
}

int main(){
    int x,y;
    x = funcp();
    y = funcp() + x;
    printf("%d\n", (x+y));
    return 0;
}

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