Question:medium

Two equal masses hung from two massless springs of spring constants $k_1$ and $k_2$ have equal maximum velocity when executing SHM. The ratio of their amplitudes is

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Higher spring constant → smaller amplitude for same maximum velocity.
Updated On: May 2, 2026
  • $\sqrt{\frac{k_1}{k_2}}$
  • $\frac{k_1}{k_2}$
  • $\frac{k_2}{k_1}$
  • $\sqrt{\frac{k_2}{k_1}}$
  • $\frac{k_1^2}{k_2^2}$
Show Solution

The Correct Option is D

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