When two dice are rolled, there are $6 \times 6 = 36$ total possible outcomes.
We seek pairs $(x,y)$ where $x \times y = 6$. The successful pairs are:
\[
(1,6), (2,3), (3,2), (6,1)
\]
This gives 4 successful outcomes.
Therefore, the probability is $\frac{4}{36}$, which simplifies to $\frac{1}{9}$.