Question

Two coins are tossed simultaneously. The probability of getting at least one head is :

• A. 1/4
• B. 1/2
• C. 3/4
• D. 1

Hint:

"At least one" is the complement of "None". Probability(at least one head) = 1 - Probability(no heads). Here, $1 - 1/4 (TT) = 3/4$.

Answer 1

The Correct Option is C

To solve the problem of finding the probability of getting at least one head when two coins are tossed simultaneously, we need to consider all possible outcomes.

1. When two coins are tossed, the possible outcomes are: 
   HH (both heads), HT (first head, second tail), TH (first tail, second head), TT (both tails).
2. Therefore, there are a total of 4 equally likely outcomes.
3. We are interested in the probability of getting at least one head. The outcomes that satisfy this condition are: HH, HT, and TH. This gives us a total of 3 favorable outcomes.
4. The probability of an event is calculated as the ratio of the number of favorable outcomes to the total number of possible outcomes.
5. Thus, the probability of getting at least one head is: \(\frac{3}{4}\).

Therefore, the correct answer is \(\frac{3}{4}\).

Let's rule out the other options:

• \(\frac{1}{4}\): This would be the probability of getting exactly one particular outcome (like two tails), not at least one head.
• \(\frac{1}{2}\): This might be mistakenly considered if only half the outcomes satisfy the condition, which isn't the case here.
• \(1\): This is the maximum probability for a certain event, but since there is a chance to get two tails, the probability isn't 1.