Congruence between two triangles means every side and every angle of one triangle matches the corresponding side and angle of the other. Equal area and equal triangle type (right-angled) are much weaker conditions than this, so the real question is whether area plus right-angled-ness pins down the full shape. It does not, and a single counterexample settles this cleanly.
Consider two right triangles with legs $(p,q)$ chosen so that $\frac12 pq$ is the same number both times:
Both triangles are right-angled (satisfying Statement II) and both have area $6$ (satisfying Statement I), yet their side lengths $3,4,5$ and $2,6,2\sqrt{10}$ do not match at all. So even with both statements assumed true simultaneously, triangle ABC and triangle PQR could be shaped like Triangle A and Triangle B above: same area, both right triangles, but not congruent.
Since a valid counterexample survives even when both statements are combined, neither statement alone, nor the two together, is enough to establish congruence. The correct choice is that the data in Statements I and II together are \(\boxed{\text{not sufficient}}\), which is option (4).