Question:medium

To upload a text document at the rate of 5 pages per 10 seconds. What will be the required data rate of the channel, assuming 1 page contain 1000 characters and each character is of 8 bits.

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Always keep track of units during calculations:
Ensure you convert characters/bytes to bits by multiplying by 8 to get the final answer in "bps" (bits per second) rather than "Bps" (Bytes per second)!
Updated On: Jun 11, 2026
  • 4000 bps
  • 6250 bps
  • 8000 bps
  • 5000 bps
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The Correct Option is A

Solution and Explanation


Step 1: Understanding the Question:

The question asks to calculate the minimum network transmission rate (data rate in bits per second, or bps) required to successfully upload 5 pages of a document in 10 seconds, given the specific sizing parameters of the pages and characters.

Step 2: Key Formulas:

To compute the channel data rate:
- Calculate the total size of a single page in bits:
\[ \text{Bits per page} = \text{Characters per page} \times \text{Bits per character} \]
- Calculate the total data size of all pages to be uploaded:
\[ \text{Total bits} = \text{Number of pages} \times \text{Bits per page} \]
- Calculate the required data rate of the channel:
\[ \text{Data Rate} = \frac{\text{Total bits}}{\text{Total time in seconds}} \]

Step 3: Detailed Step-by-Step Calculation:

- Let us extract the parameters from the problem:
- Number of pages = $5$
- Transmission time = $10 \text{ seconds}$
- Characters per page = $1000$
- Bits per character = $8 \text{ bits}$
- Calculate the number of bits in 1 page:
\[ 1000 \text{ characters} \times 8 \text{ bits/character} = 8000 \text{ bits} \]
- Calculate the total number of bits for 5 pages:
\[ 5 \text{ pages} \times 8000 \text{ bits/page} = 40000 \text{ bits} \]
- Calculate the required data rate of the channel:
\[ \text{Data Rate} = \frac{40000 \text{ bits}}{10 \text{ seconds}} = 4000 \text{ bits per second (bps)} \]
- Thus, the channel must support a minimum transmission speed of 4000 bps.

Step 4: Final Answer:

The required data rate of the channel is 4000 bps.
Hence, option (A) is the correct choice.
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