Given:
Number of examinations = 5
Marks per examination = 100
Required average for Grade ‘A’ ≥ 90
Step 1: Find minimum total marks required
Minimum total marks = 5 × 90 = 450
Step 2: Calculate total marks obtained in first four examinations
87 + 92 + 94 + 95 = 368
Step 3: Let marks in fifth examination be x
Total marks including fifth examination = 368 + x
For Grade ‘A’:
368 + x ≥ 450
Step 4: Solve the inequality
x ≥ 450 − 368
x ≥ 82
Final Answer:
The minimum marks Sunita must obtain in the fifth examination to get Grade ‘A’ is
82 marks.