Question:medium

To provide a memory capacity of 32K X 16 how many address lines and data lines are required?

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To calculate address lines: \( \text{Number of address lines} = \log_2(\text{Total locations}) \). For data lines, it is the size of the word (16 in this case).
Updated On: Mar 7, 2026
  • address lines=14 , data lines=16
  • address lines=15, data lines=16
  • address lines=14, data lines=4
  • address lines=15, data lines=4
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The Correct Option is A

Solution and Explanation

For a memory configuration of 32K X 16, the required address and data lines are determined as follows:- The total number of addressable memory locations is \( 32 \times 1024 = 32768 \).- The number of address lines is calculated using the formula: \[ \text{Number of address lines} = \log_2(32768) = 15 \text{ address lines}. \]- The number of data lines is equivalent to the word size, which is 16 bits. Thus, 16 data lines are required.Therefore, the correct configuration is address lines=15, data lines=16.
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