Question:medium

To increase the efficiency of a Carnot engine working between a source at 500 K and a sink at 300 K by 10%, with the same sink temperature the source temperature should be increased to

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Logic Tip: Note the specific phrasing "increased by 10%". In the context of engine efficiencies, this almost always refers to an absolute increase (+0.10) rather than a relative increase ($0.40 \times 1.10 = 0.44$). If it meant the latter, the answer would not be a clean integer.
Updated On: Apr 27, 2026
  • 550 K
  • 600 K
  • 700 K
  • 750 K
  • 800 K
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The Correct Option is B

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