Step 1: Use Boolean algebra
Let $G=AB$ (an AND). Then $Y=A+AB=A(1+B)=A$.
Step 2: Compare with the table
$Y=A$ reproduces all four rows: 00 gives 0, 01 gives 0, 10 gives 1, 11 gives 1. So G is an AND gate, option (C).
Final Answer:
An AND gate fits the table, option (C).
\[ \boxed{\text{AND}} \]