Question:medium
To determine the internal resistance of a cell with potentiometer, when the cell is shunted by a resistance of $5\Omega$ the balancing length is $250 \text{ cm}$. When the cell is shunted by $20\Omega$, the balancing length of potentiometer wire is $400 \text{ cm}$. The internal resistance, of the cell is
To determine the internal resistance of a cell with potentiometer, when the cell is shunted by a resistance of $5\Omega$ the balancing length is $250 \text{ cm}$. When the cell is shunted by $20\Omega$, the balancing length of potentiometer wire is $400 \text{ cm}$. The internal resistance, of the cell is
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Balancing length $l_2$ is always less than $l_1$ because terminal voltage is less than EMF.
Updated On: May 12, 2026
- $3\Omega$
- $4\Omega$
- $5\Omega$
- $6\Omega$
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The Correct Option is B
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