In a series circuit the phase angle is set by the ratio of net reactance to resistance, \(\phi=\tan^{-1}(X_{net}/R)\).
So the angle between voltage and current decreases.
The same result can be seen through the power triangle instead of the impedance triangle. In a highly inductive circuit, the reactive power is large and mostly inductive (lagging), giving a large angle between the apparent power and the real power axis. Adding series capacitance introduces a leading reactive power component that partially offsets the inductive reactive power, shrinking the net reactive power relative to the real power.
Therefore, the correct answer is decrease.