Question:medium

Threshold frequencies of the metals \(A\) and \(B\) are respectively \[ 4\times10^{14}\ \text{Hz} \] and \[ 6\times10^{14}\ \text{Hz}. \] If both are irradiated with light of frequency \[ 10^{15}\ \text{Hz}, \] what is the ratio of the kinetic energies of electrons emitted from \(A\) and \(B\)?

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For photoelectric emission, \[ K_{\max}=h(\nu-\nu_0). \] For the same incident frequency, the metal with the lower threshold frequency emits photoelectrons with greater kinetic energy.
Updated On: Jul 29, 2026
  • \(2:3\)
  • \(3:2\)
  • \(4:9\)
  • \(9:4\)
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The Correct Option is B

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