Question:medium
Three numbers \( x, y, \) and \( z \) are in arithmetic progression (A.P.). If \( x+y+z = -3 \) and \( xyz = 8 \), then \( x^2+y^2+z^2 \) is equal to:
Three numbers \( x, y, \) and \( z \) are in arithmetic progression (A.P.). If \( x+y+z = -3 \) and \( xyz = 8 \), then \( x^2+y^2+z^2 \) is equal to:
Show Hint
Always assume three A.P. terms as \( a-d, a, a+d \). If there are four, use \( a-3d, a-d, a+d, a+3d \). This symmetry simplifies the algebra significantly.
Updated On: May 1, 2026
- \( 9 \)
- \( 10 \)
- \( 21 \)
- \( 20 \)
- \( 1 \)
Show Solution
The Correct Option is C
Solution and Explanation
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