Question:medium
Three numbers are in arithmetic progression (A.P.). Their sum is 21 and the product of the first number and the third number is 45. Then the product of these three numbers is:
Three numbers are in arithmetic progression (A.P.). Their sum is 21 and the product of the first number and the third number is 45. Then the product of these three numbers is:
Show Hint
Once you find the middle term (\( a \)) and the product of the extremes (\( a^2 - d^2 \)), the total product is simply \( a \times (a^2 - d^2) \). Here, \( 7 \times 45 = 315 \). This shortcut saves you from finding \( d \) and the individual numbers.
Updated On: May 1, 2026
- 315
- 90
- 180
- 270
- 450
Show Solution
The Correct Option is A
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