Question:medium

Three identical polaroids \(P_1\), \(P_2\) and \(P_3\) are placed one after another. The pass axis of \(P_2\) and \(P_3\) are inclined at angle of \(60^{\circ}\) and \(90^{\circ}\) with respect to axis of \(P_1\). The source has an intensity \(I_0\). The intensity of light finally coming out is

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The first polaroid halves unpolarised light; Malus law applies after that.
Updated On: Oct 1, 2026
  • \(\frac{I_0}{2}cos^230^{\circ}cos^290^{\circ}\)
  • \(\frac{I_0}{2}cos^260^{\circ}cos^230^{\circ}\)
  • \(I_0cos^260^{\circ}cos^230^{\circ}\)
  • zero
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Numerical value
$\frac{I_0}{2}\times\frac14\times\frac34 = \frac{3I_0}{32}$.

Step 2: Matching
Only option (B) has the factor $\frac{I_0}{2}$ with angles $60^{\circ}$ and $30^{\circ}$ between successive axes.

Final Answer:
Option B. \[ \boxed{\text{(B)}\ \frac{I_0}{2}\cos^260^{\circ}\cos^230^{\circ}} \]
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