Question:medium

There is a galvanometer of resistance $100\Omega$ and full scale current $I_g = 1$ mA. Find shunt resistance required to increase its range to $5$ mA.

Show Hint

Shunt resistance is always much smaller than galvanometer resistance.
Updated On: Mar 25, 2026
  • $25\Omega$
  • $0.25\Omega$
  • $0.5\Omega$
  • $1\Omega$
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Understand the purpose of the shunt

To extend the current range of a galvanometer, a low resistance called a shunt is connected in parallel with it so that most of the current bypasses the galvanometer.


Step 2: Write the formula for shunt resistance

The shunt resistance Rs is given by:

Rs = (Rg · Ig) / (I − Ig)

where
Rg = resistance of galvanometer
Ig = full-scale deflection current of galvanometer
I = desired maximum current


Step 3: Substitute the given values

Rg = 100 Ω
Ig = 1 mA = 0.001 A
I = 5 mA = 0.005 A

Rs = (100 × 0.001) / (0.005 − 0.001)


Step 4: Perform the calculation

Rs = 0.1 / 0.004

Rs = 25 Ω


Final Answer:

The shunt resistance required is
25 Ω

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