To solve this problem, we need to find the minimum number of books that can be distributed equally among students of either Section A or Section B. This requires determining the Least Common Multiple (LCM) of the number of students in Section A and Section B.
- Identify the number of students in each section:
- Section A: 28 students
- Section B: 30 students
- Calculate the LCM of the numbers 28 and 30. The LCM is the smallest positive integer that is divisible by both these numbers.
- Find the prime factorization of each number:
- 28: \(28 = 2^2 \times 7\)
- 30: \(30 = 2 \times 3 \times 5\)
- Determine the LCM by taking the highest power of each prime number present in the factorizations:
- For 2: highest power is \(2^2\)
- For 3: highest power is \(3^1\)
- For 5: highest power is \(5^1\)
- For 7: highest power is \(7^1\)
- Compute the LCM: \(\text{LCM} = 2^2 \times 3^1 \times 5^1 \times 7^1 = 4 \times 3 \times 5 \times 7 = 420\)
- Therefore, the smallest number of books needed to distribute them equally among students of either section is 420.
Hence, the correct answer is 420.