There are 720 permutations of the digits 1, 2 ,3 , 4, 5, 6 suppose these permutations are arranged from smallest to largest numerical values beginning from 123456 and and ending with 654321.Whihc of the following is correct?
Number on the 124th position is 213564
Number on the 267th position is 321546
Number on the 124th position is 213546
Number on the 267th position is 321564
To solve this problem, we need to find the permutation of the set of digits \( \{1, 2, 3, 4, 5, 6\} \) at specific positions when all permutations are arranged in ascending order. There are \( 6! = 720 \) such permutations.
Let's break it down using the concept of lexicographic order:
Each set of permutations where a particular starting digit is fixed contains \( 5! = 120 \) permutations (since the remaining five digits can be arranged in \( 5! \) ways).
We need to find out which digits start the permutations for the 124th and 267th positions.
Finding the 124th permutation:
Finding the 267th permutation:
In conclusion, the results match the listed options and we have: