Question

The work function of a metal is 5 eV. What is the kinetic energy of the photoelectron ejected from the metal surface if the energy of the incident radiation is 6.2 eV? ($1 \text{ eV} = 1.6 \times 10^{-19} \text{ J}$)

• A. $6.626 \times 10^{-19} \text{ J}$
• B. $8.01 \times 10^{-19} \text{ J}$
• C. $1.92 \times 10^{-18} \text{ J}$
• D. $8.010 \times 10^{-18} \text{ J}$
• E. $1.92 \times 10^{-19} \text{ J}$

Hint:

If the incident energy is less than the work function ($E < \Phi$), no photoelectrons will be ejected, regardless of the intensity of the light!

Answer 1

Answer: (E)