Question:medium
The wavelength of a fast moving particle (\(\lambda\)) is related to its momentum (p) and Planck’s constant (h) as
The wavelength of a fast moving particle (\(\lambda\)) is related to its momentum (p) and Planck’s constant (h) as
Show Hint
Remember that high momentum (larger mass or higher velocity) means a shorter wavelength.
This is why macroscopic objects do not show noticeable wave properties.
This is why macroscopic objects do not show noticeable wave properties.
Updated On: Apr 29, 2026
- \(\lambda = hp\)
- \(\lambda = h^2 / p\)
- \(\lambda = h / p\)
- \(\lambda = p^2 / h\)
- \(\lambda = h / p^2\)
Show Solution
The Correct Option is C
Solution and Explanation
Was this answer helpful?
0
Top Questions on Dual nature of matter
- A material particle with a rest mass m₀ is moving with a velocity of light c. Then the wavelength of the de Broglie wave associated with it is
- BITSAT - 2010
- Chemistry
- Dual nature of matter
- An \( \alpha \)-particle, a proton, and an electron have the same kinetic energy. Which one of the following is correct in case of their De-Broglie wavelength:
- JEE Main - 2023
- Chemistry
- Dual nature of matter
- If a cricket ball having mass of 200 g is thrown with a speed of \( 3 \times 10^{3} \text{ cm/s} \), then calculate the wavelength related to it.
- MET - 2008
- Chemistry
- Dual nature of matter
- The de-Broglie wavelength of an electron accelerated through a potential difference of 100 V is:
- MET - 2008
- Chemistry
- Dual nature of matter
- Want to practice more? Try solving extra ecology questions todayView All Questions
