Step 1: Approach
Compute the cross product of two edges and dot it with the third.
Step 2: Cross product
$\vec b\times\vec c=(3,-1,-1)\times(0,1,3)=((-1)(3)-(-1)(1),\ (-1)(0)-3\cdot3,\ 3\cdot1-0)=(-2,-9,3)$.
Step 3: Dot with a
$(2,1,-1)\cdot(-2,-9,3)=-4-9-3=-16$.
Step 4: Volume
The magnitude is 16 cubic units, option (A).
Final Answer:
The determinant of the three edges is -16, so the volume is 16 cubic units, option (A).
\[ \boxed{16\ \text{cu. units}} \]