Step 1: Apply Boyle's law (constant temperature).
\( P_1 V_1 = P_2 V_2 \). Given \( P_1 = 760\,\text{mm Hg} \), \( V_1 = 100\,\text{cc} \), \( P_2 = 400\,\text{mm Hg} \).
Step 2: Solve for \( V_2 \).
\[ V_2 = \frac{P_1 V_1}{P_2} = \frac{760\times100}{400} = 190\,\text{cc} \] \[ \boxed{190\,\text{cc}} \]