Question:medium
The vertex of the parabola \( 4y = x^2 - 6x + 17 \) is
The vertex of the parabola \( 4y = x^2 - 6x + 17 \) is
Show Hint
Vertex form comes after completing square: \( y = a(x-h)^2 + k \Rightarrow (h,k) \).
Updated On: Apr 21, 2026
- \( (3,2) \)
- \( (4,3) \)
- \( (4,2) \)
- \( (3,7) \)
- \( (7,2) \)
Show Solution
The Correct Option is A
Solution and Explanation
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