Question:medium
The vertex of a parabola is at $(2,-5)$ and the focus is at $(5,-5)$. The equation of the parabola is
The vertex of a parabola is at $(2,-5)$ and the focus is at $(5,-5)$. The equation of the parabola is
Show Hint
If focus is right of vertex, parabola opens right: use $(y-k)^2 = 4a(x-h)$.
Updated On: Apr 24, 2026
- $y^2 + 10y - 10x + 49 = 0$
- $y^2 + 10y - 12x + 49 = 0$
- $y^2 + 10y - 12x + 46 = 0$
- $y^2 + 8y - 12x + 49 = 0$
- $y^2 + 10y - 18x + 48 = 0$
Show Solution
The Correct Option is B
Solution and Explanation
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