Question:medium

The velocity distribution of a viscous liquid ($\mu = 0.9 \text{ N-s/m}^2$) over a fixed boundary is given by $u = 0.68y - y^2$, in which $u$ is the velocity in m/s at a distance $y$ meters above the boundary surface. Determine the shear stress at the surface.

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The "surface" or "boundary" always implies $y = 0$. Always check if the units of viscosity are in SI (N-s/m$^2$ or Pa-s) or Poise ($1 \text{ Pa-s} = 10 \text{ Poise}$) before calculating!
Updated On: May 20, 2026
  • $0.512 \text{ N/m}^2$
  • $0.0 \text{ N/m}^2$
  • $0.6 \text{ N/m}^2$
  • $0.612 \text{ N/m}^2$
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The Correct Option is D

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