The vectors $\vec{p} = \hat{i} + a\hat{j} + a^2\hat{k}, \vec{q} = \hat{i} + b\hat{j} + b^2\hat{k}$ and $\vec{r} = \hat{i} + c\hat{j} + c^2\hat{k}$ are non-coplanar and $\begin{vmatrix} a & a^2 & 1+a^3 \\ b & b^2 & 1+b^3 \\ c & c^2 & 1+c^3 \end{vmatrix} = 0$ then the value of $(abc)$ is
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Determinant property: $\begin{vmatrix} x & y & z+w \end{vmatrix} = \begin{vmatrix} x & y & z \end{vmatrix} + \begin{vmatrix} x & y & w \end{vmatrix}$.