Question:medium

The variance of the first $n$ even natural numbers is:

Show Hint

Since the first $n$ natural numbers have a variance of $\frac{n^2-1}{12}$, scaling them by 2 (even numbers) scales the variance by $2^2 = 4$. Thus, $4 \times \frac{n^2-1}{12} = \frac{n^2-1}{3}$.
Updated On: May 31, 2026
  • $\frac{n^2 - 1}{12}$
  • $\frac{n^2 - 1}{3}$
  • $\frac{n^2 + 1}{3}$
  • $\frac{n^2 - 1}{4}$
Show Solution

The Correct Option is B

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