Question:medium

The value of $\vec{\nabla}\left(\frac{f}{g}\right)$ at points where $g(x) \neq 0$ is given by

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Vector differential operators ($\vec{\nabla}$) mirror single-variable calculus rules: - Product Rule: $\vec{\nabla}(f g) = f \vec{\nabla} g + g \vec{\nabla} f$ - Quotient Rule: $\vec{\nabla}(f/g) = \frac{g \vec{\nabla} f - f \vec{\nabla} g}{g^2}$
Updated On: Jul 29, 2026
  • $f \vec{\nabla} g - g \vec{\nabla} f$
  • $\frac{g \vec{\nabla} f - f \vec{\nabla} g}{g^2}$
  • $\frac{f \vec{\nabla} g - g \vec{\nabla} f}{g^2}$
  • $g \vec{\nabla} f - f \vec{\nabla} g$
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The Correct Option is B

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