Question:medium

The value of \(|\vec{a} \times \vec{b} + \vec{b} \times \vec{a}|\) is

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\(\vec{a} \times \vec{b}\) and \(\vec{b} \times \vec{a}\) are equal in magnitude but opposite in direction.
Updated On: Apr 18, 2026
  • 1
  • \(2|\vec{a} \times \vec{b}|\)
  • 0
  • None of these
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept:
The cross product of two vectors is anti-commutative. This means that the direction of the product vector flips when the order of the operands is reversed.
Step 2: Detailed Explanation:
By the property of vector products (cross products): \[ \vec{a} \times \vec{b} = - (\vec{b} \times \vec{a}) \] Alternatively: \[ \vec{b} \times \vec{a} = - (\vec{a} \times \vec{b}) \] Now, look at the expression inside the magnitude sign: \[ \vec{a} \times \vec{b} + \vec{b} \times \vec{a} \] Substituting \( \vec{b} \times \vec{a} = - (\vec{a} \times \vec{b}) \): \[ = \vec{a} \times \vec{b} + (- \vec{a} \times \vec{b}) \] \[ = \vec{a} \times \vec{b} - \vec{a} \times \vec{b} = \vec{0} \] The magnitude of a zero vector is 0. \[ |\vec{0}| = 0 \].
Step 3: Final Answer:
The value is 0.
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