Question:medium

The value of the limit $\lim_{x \to 0} \frac{e^{3x} - e^{-2x}}{\sin 4x}$ is:

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For $\lim_{x\to 0} \frac{e^{ax} - e^{-bx}}{\sin cx}$, the value of the limit simplifies directly to $\frac{a+b}{c}$. Here, $\frac{3 - (-2)}{4} = \frac{5}{4}$.
Updated On: May 31, 2026
  • $\frac{5}{4}$
  • $\frac{1}{4}$
  • $\frac{3}{4}$
  • $\frac{1}{2}$
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The Correct Option is A

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