To solve the integral
\[\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \frac{1}{[x]+4}\,dx\] where \([x]\) denotes the greatest integer function, we need to analyze the behavior of the function inside the integral.
- First, understand the range of \(x\) and how the greatest integer function \([x]\) behaves. The greatest integer function, \([x]\), returns the greatest integer less than or equal to \(x\).
- The interval of integration is \([-\frac{\pi}{2}, \frac{\pi}{2}]\). We approximate \(\pi \approx 3.14\), so \(-\frac{\pi}{2} \approx -1.57\) and \(\frac{\pi}{2} \approx 1.57\).
- Analyze \([x]\) in this interval:
- For \(x \in [-\frac{\pi}{2}, -1)\), \([x] = -2\).
- For \(x \in [-1, 0)\), \([x] = -1\).
- For \(x \in [0, 1)\), \([x] = 0\).
- For \(x \in [1, \frac{\pi}{2}]\), \([x] = 1\).
- Split the integral based on these intervals:
- Calculate each integral separately:
- \(\int_{-\frac{\pi}{2}}^{-1} \frac{1}{2}\,dx = \frac{1}{2}\left([-1] - \left(-\frac{\pi}{2}\right)\right) = \frac{1}{2}(1 + \frac{\pi}{2})\)
- \(\int_{-1}^{0} \frac{1}{3}\,dx = \frac{1}{3}[0 - (-1)] = \frac{1}{3}\)
- \(\int_{0}^{1} \frac{1}{4}\,dx = \frac{1}{4}[1 - 0] = \frac{1}{4}\)
- \(\int_{1}^{\frac{\pi}{2}} \frac{1}{5}\,dx = \frac{1}{5}(\frac{\pi}{2} - 1)\)
- Add these results together:
- Combine and simplify:
- By further simplification, combine terms with \(\pi\) and constant terms:
Therefore, the value of the integral is \(\frac{7}{60} (3\pi - 1)\), which corresponds to the correct answer. Thus, the correct answer is:
The value of the integral is: \(\frac{7}{60} (3\pi - 1)\)