Step 1: Reduce step by step
Each shift of $\pi$ returns tangent to its own value, because $\tan(x-\pi)=\frac{\sin(x-\pi)}{\cos(x-\pi)}=\frac{-\sin x}{-\cos x}=\tan x$.
Doing this $9$ times keeps the value as $\tan x$. Option (C).
Final Answer:
Option (C).
\[ \boxed{\text{(C)}} \]