Question:medium
The value of the determinant \( \begin{vmatrix} 1 & 1 & 1 \\ p & q & r \\ p & q & r+1 \end{vmatrix} \) is equal to:
The value of the determinant \( \begin{vmatrix} 1 & 1 & 1 \\ p & q & r \\ p & q & r+1 \end{vmatrix} \) is equal to:
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Whenever you see two rows that are almost identical, subtract them immediately. This "Zero-Creation" strategy is the fastest way to solve competitive exam questions involving determinants.
Updated On: May 1, 2026
- \( q - p \)
- \( q + p \)
- \( q \)
- \( p \)
- \( 0 \)
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The Correct Option is A
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