Question:hard

The value of the definite integral \(\int _0^{log_e5}\frac{e^x\sqrt{e^x-1}}{e^x+3}\,dx\) is equal to...

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Substitute t = sqrt(e^x - 1) to remove the square root.
Updated On: Oct 1, 2026
  • \(5+π\)
  • \(5-π\)
  • \(4+π\)
  • \(4-π\)
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Quick sanity check:
The integrand is positive and small near $0$ and about $\frac{5\times 2}{8} = 1.25$ at the upper limit, over an interval of length about $1.61$, so the integral should be of order $1$.

Step 2: Compute:
$4 - \pi \approx 0.858$. The options $5 \pm \pi$ and $4 + \pi$ are far larger, and the careful substitution gives exactly $4 - \pi$.

Final Answer:
The integral equals $4 - \pi$, option (D). \[ \boxed{4-\pi} \]
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