Question:medium
The value of
\[
\tan\!\left(\tan^{-1}(3)+\tan^{-1}(7)\right)
\]
is equal to:
The value of
\[
\tan\!\left(\tan^{-1}(3)+\tan^{-1}(7)\right)
\]
is equal to:
Show Hint
Since \(3 \times 7 > 1\), the angle \(\tan^{-1}(3) + \tan^{-1}(7)\) will be greater than \(\frac{\pi}{2}\). This explains why the tangent value is negative (it falls in the second quadrant).
Updated On: Jun 25, 2026
- \(-\frac{1}{2}\)
- \(\frac{1}{2}\)
- \(\frac{1}{5}\)
- \(-\frac{1}{5}\)
- 0
Show Solution
The Correct Option is A
Solution and Explanation
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