Question:medium
The value of $\sin6^\circ \cos36^\circ \sin66^\circ + \cos12^\circ \sin42^\circ \sin18^\circ$ is equal to:
The value of $\sin6^\circ \cos36^\circ \sin66^\circ + \cos12^\circ \sin42^\circ \sin18^\circ$ is equal to:
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Use product-to-sum identities to simplify multiple trig product terms.
Updated On: Apr 24, 2026
- $\frac{1}{12}(\sin18^\circ + \cos36^\circ)$
- $\frac{1}{3}(\sin18^\circ + \cos36^\circ)$
- $\frac{1}{16}(\sin18^\circ + \cos36^\circ)$
- $\frac{1}{4}(\sin18^\circ + \cos36^\circ)$
- $\frac{1}{2}(\sin18^\circ + \cos36^\circ)$
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The Correct Option is D
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