Question:medium
The value of $\sin^{-1}\left(\sin \dfrac{5\pi}{9} \cos \dfrac{\pi}{9} + \sin \dfrac{\pi}{9} \cos \dfrac{5\pi}{9}\right)$ is equal to:
The value of $\sin^{-1}\left(\sin \dfrac{5\pi}{9} \cos \dfrac{\pi}{9} + \sin \dfrac{\pi}{9} \cos \dfrac{5\pi}{9}\right)$ is equal to:
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Always convert expressions using identities before applying inverse functions.
Updated On: Apr 24, 2026
- $\frac{2\pi}{3}$
- $\frac{\pi}{2}$
- $\frac{\pi}{6}$
- $\frac{\pi}{3}$
- $\frac{\pi}{9}$
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The Correct Option is D
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