Question:medium
The value of $\lim_{x \to 0} \frac{\cot 4x}{\csc 3x}$ is equal to:
The value of $\lim_{x \to 0} \frac{\cot 4x}{\csc 3x}$ is equal to:
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For limits of the form $\frac{\tan mx}{\sin nx}$ or $\frac{\sin mx}{\sin nx}$ as $x \to 0$, the result is always the ratio of the coefficients, $\frac{m}{n}$.
Updated On: May 2, 2026
- $\frac{4}{3}$
- $\frac{3}{4}$
- $\frac{2}{3}$
- $\frac{3}{2}$
- $0$
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The Correct Option is B
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