Question:medium
The value of
\[
\left[\frac{5i}{(3+i)(3-i)}\right]^{2026}
\]
is equal to:
The value of
\[
\left[\frac{5i}{(3+i)(3-i)}\right]^{2026}
\]
is equal to:
Show Hint
To evaluate any high power of \(i\), just look at the last two digits of the exponent. \(26 \pmod 4 = 2\). Thus, \(i^{2026} = i^2 = -1\).
Updated On: Jun 25, 2026
- \(\frac{1}{2^{2026}}\)
- \(\frac{1}{2^{1013}}\)
- \(\frac{-1}{2^{1013}}\)
- \(\frac{i}{2^{2026}}\)
- \(\frac{-1}{2^{2026}}\)
Show Solution
The Correct Option is
Solution and Explanation
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