Step 1: Bound the derivative:
By Cauchy-Schwarz, $|\cos x+\sin x|\leq\sqrt{1^2+1^2}=\sqrt2$, with equality when $\tan x=1$.
Step 2: Apply the requirement:
For $f'<0$ at the worst case we need $\sqrt2-k<0$, so $k>\sqrt2$.
Step 3: Pick:
Option D.
Final Answer:
The maximum of cos x + sin x is sqrt 2, so k must exceed it.
\[ \boxed{\text{(D) }k>\sqrt2} \]